A small mass m is released from rest at the top of a frictionless solid sphere. it slides down the sphere and eventually falls off. at what angle from the vertical does the mass lose contact with the sphere. (Hint: the normal force between the mass and the sphere drops to zero when the acceleration of the mass drops below V^2/r . you will need to combine the force equation and the energy conservation equation)

**Introduction**

Don't use plagiarized sources. Get Your Custom Essay on

What happens to the normal force between a small mass and a frictionless solid sphere when the acceleration of the mass drops below V^2/r?

Just from $13/Page

The motion of a small mass m on a frictionless solid sphere is an interesting phenomenon to investigate in physics. This scenario presents a challenging question: at what angle from the vertical does the mass lose contact with the sphere? In this discussion, we will delve deeper into the mechanics behind the situation and apply the force equation and energy conservation equation.

**Description**

In this scenario, a small mass m is released from rest at the top of a frictionless solid sphere. The objective is to determine the angle at which the mass loses contact with the sphere once it slides down the surface and eventually falls off. To solve this problem, the force equation and energy conservation equation must be merged. The normal force experienced by the mass and the sphere drops to zero when the acceleration of the mass falls below V^2/r. Hence, its acceleration is dependant on gravity. The angle at which the mass loses contact with the sphere can be determined by calculating the gravitational force acting on the mass, which is the force responsible for providing the necessary centripetal force for the mass to move in a circular motion around the sphere. By equating the gravitational force and the centripetal force, the angle can be calculated.

Objectives:

– To understand the concept of normal force and its relation to the acceleration of an object on a frictionless surface.

– To learn about the use of force and energy conservation equations in solving problems involving motion on curved surfaces.

– To apply the concept of centrifugal force in determining the angle at which an object loses contact with a solid sphere.

Learning Outcomes:

By the end of this lesson, learners will be able to:

– Explain the relationship between the normal force and the acceleration of an object on a frictionless solid sphere.

– Apply the force equation and the energy conservation equation to solve problems involving motion on curved surfaces.

– Calculate the angle at which a small mass loses contact with a solid sphere, given the mass of the object and the radius of the sphere.

Solution 1: Determining the Angle Using the Force Equation and Energy Conservation Equation

To determine the angle from the vertical at which the small mass m loses contact with the sphere, we need to use the force equation and the energy conservation equation. We know that the normal force between the mass and the sphere drops to zero when the acceleration of the mass drops below V^2/r.

We can calculate the velocity of the mass as it slides down the sphere using the conservation of energy equation:

mgh = (1/2)mv^2

where m is the mass of the small mass, g is the acceleration due to gravity, h is the height of the sphere, v is the velocity of the mass.

When the mass loses contact with the sphere, the gravitational force on the mass is balanced by the centrifugal force. Using the force equation, we can equate these two forces:

mg cos θ = mV^2 / r

where θ is the angle from the vertical at which the mass loses contact with the sphere, r is the radius of the sphere, V is the velocity of the mass at that point.

We can substitute the value of the velocity of the mass obtained from the conservation of energy equation in the force equation:

mg cos θ = m (2gh) / r

Solving for θ:

cos θ = 2h / r

θ = cos^-1 (2h/r)

Therefore, the angle from the vertical at which the small mass m loses contact with the sphere is θ = cos^-1 (2h/r).

Solution 2: Using the Law of Conservation of Energy to Find the Angle

To determine the angle at which the small mass m loses contact with the sphere, we can also use the law of conservation of energy. We know that when the mass loses contact with the sphere, its total energy is equal to its kinetic energy:

mgh = (1/2)mv^2

where m is the mass of the small mass, g is the acceleration due to gravity, h is the height of the sphere, v is the velocity of the mass.

We also know that the potential energy at the point where it loses contact with the sphere is zero.

At that point, the centrifugal force and the gravitational force balance each other. We can equate these two forces:

mg cos θ = mV^2 / r

where θ is the angle from the vertical at which the mass loses contact with the sphere, r is the radius of the sphere, V is the velocity of the mass at that point.

We can substitute the value of the velocity of the mass obtained from the conservation of energy equation in the force equation and solve for θ.

mgh = (1/2)m (V^2)

V^2 = 2gh

Substituting the value of V^2 in the force equation:

mg cos θ = m (2gh) / r

Solving for θ:

cos θ = 2h / r

θ = cos^-1 (2h/r)

Therefore, the angle from the vertical at which the small mass m loses contact with the sphere is θ = cos^-1 (2h/r).

Suggested Resources/Books:

1. University Physics with Modern Physics by Young and Freedman

2. Introduction to Classical Mechanics by David Morin

3. Physics for Scientists and Engineers by Serway and Jewett

Similar Asked Questions:

1. What is the minimum speed required for an object to maintain contact with a vertical loop?

2. How is the force of friction related to the normal force?

3. What is the relationship between potential energy and kinetic energy at different points in a roller coaster ride?

4. How does the acceleration of a mass on an inclined plane depend on the angle of the incline?

5. What is the difference between static friction and kinetic friction?A small mass m is released from rest at the top of a frictionless solid sphere. it slides down the sphere and eventually falls off. at what angle from the vertical does the mass lose contact with the sphere. (Hint: the normal force between the mass and the sphere drops to zero when the acceleration of the mass drops below V^2/r . you will need to combine the force equation and the energy conservation equation)

**Introduction**

The motion of a small mass m on a frictionless solid sphere is an interesting phenomenon to investigate in physics. This scenario presents a challenging question: at what angle from the vertical does the mass lose contact with the sphere? In this discussion, we will delve deeper into the mechanics behind the situation and apply the force equation and energy conservation equation.

**Description**

In this scenario, a small mass m is released from rest at the top of a frictionless solid sphere. The objective is to determine the angle at which the mass loses contact with the sphere once it slides down the surface and eventually falls off. To solve this problem, the force equation and energy conservation equation must be merged. The normal force experienced by the mass and the sphere drops to zero when the acceleration of the mass falls below V^2/r. Hence, its acceleration is dependant on gravity. The angle at which the mass loses contact with the sphere can be determined by calculating the gravitational force acting on the mass, which is the force responsible for providing the necessary centripetal force for the mass to move in a circular motion around the sphere. By equating the gravitational force and the centripetal force, the angle can be calculated.

Objectives:

– To understand the concept of normal force and its relation to the acceleration of an object on a frictionless surface.

– To learn about the use of force and energy conservation equations in solving problems involving motion on curved surfaces.

– To apply the concept of centrifugal force in determining the angle at which an object loses contact with a solid sphere.

Learning Outcomes:

By the end of this lesson, learners will be able to:

– Explain the relationship between the normal force and the acceleration of an object on a frictionless solid sphere.

– Apply the force equation and the energy conservation equation to solve problems involving motion on curved surfaces.

– Calculate the angle at which a small mass loses contact with a solid sphere, given the mass of the object and the radius of the sphere.

Solution 1: Determining the Angle Using the Force Equation and Energy Conservation Equation

To determine the angle from the vertical at which the small mass m loses contact with the sphere, we need to use the force equation and the energy conservation equation. We know that the normal force between the mass and the sphere drops to zero when the acceleration of the mass drops below V^2/r.

We can calculate the velocity of the mass as it slides down the sphere using the conservation of energy equation:

mgh = (1/2)mv^2

where m is the mass of the small mass, g is the acceleration due to gravity, h is the height of the sphere, v is the velocity of the mass.

When the mass loses contact with the sphere, the gravitational force on the mass is balanced by the centrifugal force. Using the force equation, we can equate these two forces:

mg cos θ = mV^2 / r

where θ is the angle from the vertical at which the mass loses contact with the sphere, r is the radius of the sphere, V is the velocity of the mass at that point.

We can substitute the value of the velocity of the mass obtained from the conservation of energy equation in the force equation:

mg cos θ = m (2gh) / r

Solving for θ:

cos θ = 2h / r

θ = cos^-1 (2h/r)

Therefore, the angle from the vertical at which the small mass m loses contact with the sphere is θ = cos^-1 (2h/r).

Solution 2: Using the Law of Conservation of Energy to Find the Angle

To determine the angle at which the small mass m loses contact with the sphere, we can also use the law of conservation of energy. We know that when the mass loses contact with the sphere, its total energy is equal to its kinetic energy:

mgh = (1/2)mv^2

We also know that the potential energy at the point where it loses contact with the sphere is zero.

At that point, the centrifugal force and the gravitational force balance each other. We can equate these two forces:

mg cos θ = mV^2 / r

We can substitute the value of the velocity of the mass obtained from the conservation of energy equation in the force equation and solve for θ.

mgh = (1/2)m (V^2)

V^2 = 2gh

Substituting the value of V^2 in the force equation:

mg cos θ = m (2gh) / r

Solving for θ:

cos θ = 2h / r

θ = cos^-1 (2h/r)

Suggested Resources/Books:

1. University Physics with Modern Physics by Young and Freedman

2. Introduction to Classical Mechanics by David Morin

3. Physics for Scientists and Engineers by Serway and Jewett

Similar Asked Questions:

1. What is the minimum speed required for an object to maintain contact with a vertical loop?

2. How is the force of friction related to the normal force?

3. What is the relationship between potential energy and kinetic energy at different points in a roller coaster ride?

4. How does the acceleration of a mass on an inclined plane depend on the angle of the incline?

5. What is the difference between static friction and kinetic friction?

Basic features

- Free title page and bibliography
- Unlimited revisions
- Plagiarism-free guarantee
- Money-back guarantee
- 24/7 support

On-demand options

- Writer’s samples
- Part-by-part delivery
- Overnight delivery
- Copies of used sources
- Expert Proofreading

Paper format

- 275 words per page
- 12 pt Arial/Times New Roman
- Double line spacing
- Any citation style (APA, MLA, Chicago/Turabian, Harvard)

Delivering a high-quality product at a reasonable price is not enough anymore.

That’s why we have developed 5 beneficial guarantees that will make your experience with our service enjoyable, easy, and safe.

You have to be 100% sure of the quality of your product to give a money-back guarantee. This describes us perfectly. Make sure that this guarantee is totally transparent.

Read moreEach paper is composed from scratch, according to your instructions. It is then checked by our plagiarism-detection software. There is no gap where plagiarism could squeeze in.

Read moreThanks to our free revisions, there is no way for you to be unsatisfied. We will work on your paper until you are completely happy with the result.

Read moreYour email is safe, as we store it according to international data protection rules. Your bank details are secure, as we use only reliable payment systems.

Read moreBy sending us your money, you buy the service we provide. Check out our terms and conditions if you prefer business talks to be laid out in official language.

Read more